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March 30, 2017

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In the accompanying diagram, abcd is a rectangle with ab as a diameter of semicircle o. Diagonal bd is drawn in rectangle abcd. The length of bd exceeds the length of ab by 1, and ad=5. Please help thank you

  • Math - ,

    Let x=mAB
    then
    mBD=x+1
    Since mAB=5, we apply Pythagoras Theorem to get
    (mBD)²=(mAB)²+(mAD)²
    All of the measures are either know or can be expressed in terms of x.
    Solve for x.

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