Posted by Kiki on .
In the accompanying diagram, abcd is a rectangle with ab as a diameter of semicircle o. Diagonal bd is drawn in rectangle abcd. The length of bd exceeds the length of ab by 1, and ad=5. Please help thank you

Math 
MathMate,
Let x=mAB
then
mBD=x+1
Since mAB=5, we apply Pythagoras Theorem to get
(mBD)²=(mAB)²+(mAD)²
All of the measures are either know or can be expressed in terms of x.
Solve for x.