A student weighs 36.4kg suppose his entire body is made of electrons. How many electrons are present in his body. What would be charge in his body.
To calculate the number of electrons in the student's body, we need to use Avogadro's number and the student's weight.
1. Determine the student's mass: The weight of the student is given as 36.4 kg. Mass and weight are related, so the student's mass is also 36.4 kg.
2. Convert the mass to grams: Since Avogadro's number is typically given in terms of particles per mole, we need to convert the mass from kg to grams. Therefore, we multiply the mass by 1000:
Mass = 36.4 kg × 1000 g/kg = 36400 g
3. Calculate the number of moles: To convert the mass to moles, we need to use the molar mass of an electron. The molar mass of an electron is extremely small and is approximately 5.48579909070 × 10^-7 g/mol.
Number of moles = Mass / Molar mass
Number of moles = 36400 g / (5.48579909070 × 10^-7 g/mol)
4. Apply Avogadro's number: Avogadro's number represents the number of particles in one mole of a substance and is approximately 6.022 × 10^23 particles/mol.
Number of electrons = Number of moles × Avogadro's number
To calculate the charge in the student's body, we need to determine the total charge of all the electrons.
5. Determine the charge of one electron: The elementary charge, denoted as "e", is the charge of an electron, which is approximately -1.602 x 10^-19 coulombs.
6. Calculate the total charge: Multiply the number of electrons by the charge of one electron.
Total charge = Number of electrons × Charge of one electron
Now, let's perform the calculations:
Step 1: Mass = 36.4 kg
Step 2: Mass = 36400 g
Step 3: Number of moles = 36400 g / (5.48579909070 × 10^-7 g/mol)
Step 4: Number of electrons = Number of moles × Avogadro's number
Step 5: Charge of one electron = -1.602 x 10^-19 C
Step 6: Total charge = Number of electrons × Charge of one electron
By following these steps and plugging in the values, you will be able to determine the number of electrons present in the student's body as well as the charge.