Posted by **Riana** on Sunday, December 23, 2012 at 1:35am.

A certain antibioyic reducesthe number of bacteria in your body by 10% each dose

a) if four doses of the antibiotic are taken, what percent of the original bacterial population is left.

b) biologists have determined that when a person has a bacterial infection, if the bacterial level can be reduced to 5% of its population, the person can fight off the infection. How many doses must be administered to reduce the bacterial population to the desired level?

Its a geometric question.

- math -
**drwls**, Sunday, December 23, 2012 at 2:58am
a) (0.9)^4 = 0.656 = 65.6% of original remains

b) Solve (0.9)^N = 0.05 for N

N = log(0.05)/log(0.9]= 28.4

- math -
**Riana**, Sunday, December 23, 2012 at 7:33pm
Its shud be done without using log

- math -
**MathMate**, Tuesday, December 25, 2012 at 11:03am
Without log, you only have to multiply 1.0 by 0.9 as many times as need to get a product of 0.05. I get 0.052 after multiplying 28 times and 0.047 after multiplying 29 times.

So the answer is between 28 to 29 doses.

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