Homework Help: Calculus

Posted by Lost One on Friday, December 21, 2012 at 12:03pm.

a 5m ladder rests against a vertical wall. The top of the ladder begins sliding down the wall at 2m/sec, while the foot of the ladder moves away from the base of the wall. How fast is the foot of the ladder moving away from the wall at the instant the foot of the ladder is 4m from the base of the wall?

Calculus - Steve, Friday, December 21, 2012 at 12:14pm
when x=4, y=3

x^2+y^2 = 25
2x dx/dt + 2y dy/dt = 0
2(4) dx/dt + 2(3)(-2) = 0
dx/dt = 12/8 = 1.5 m/s

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