Posted by Anonymous on Friday, December 21, 2012 at 12:57am.
An object is thrown vertically upward such
that it has a speed of 56 m/s when it reaches
two thirds of its maximum height above the
launch point.
Find the maximum height h. The acceleration of gravity is 9.8 m/s
2
.
Answer in units of m

physics  drwls, Friday, December 21, 2012 at 3:16am
At 2/3 of its maximum height, it has 1/3 of its initial kinetic energy left. That means it has 1/sqrt3 = 0.5773 of its initial velocity. The initial velocity must have been
Vo = 56/0.5773 = 96.99 m/s.
Max height is Vo^2/(2*g)
= 480 m

physics  salah ns, Thursday, October 6, 2016 at 3:17pm
v.=56m/s
v=0
g=10m/s2
v2=V.2+2gyx
0=31362.9.8.x
19.6x=3136m
x=160m
1/3x=160m
x=3.160=480m
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