Posted by **Anonymous** on Friday, December 21, 2012 at 12:57am.

An object is thrown vertically upward such

that it has a speed of 56 m/s when it reaches

two thirds of its maximum height above the

launch point.

Find the maximum height h. The acceleration of gravity is 9.8 m/s

2

.

Answer in units of m

- physics -
**drwls**, Friday, December 21, 2012 at 3:16am
At 2/3 of its maximum height, it has 1/3 of its initial kinetic energy left. That means it has 1/sqrt3 = 0.5773 of its initial velocity. The initial velocity must have been

Vo = 56/0.5773 = 96.99 m/s.

Max height is Vo^2/(2*g)

= 480 m

- physics -
**salah ns**, Thursday, October 6, 2016 at 3:17pm
v.=56m/s

v=0

g=-10m/s2

v2=V.2+2gyx

0=3136-2.9.8.x

19.6x=3136m

x=160m

1/3x=160m

x=3.160=480m

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