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posted by sandra on Friday, December 21, 2012 at 12:54am.
f(x)=x^3-2x^2+x and f'(x)=3x^2-4x+1 Find the value(s) of x where f(x) has a horizontal tangent (slope=0)
horizontal slope means f' = 0 f'(x) = (3x-1)(x+1) now it should be clear.
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