What is the frictional force between the tires of a 2000 kg car and an asphalt road if the coefficient of friction is 1.2?
Are the tires rolling or skidding? If rolling, it depends upon whether the car is accelerating or not. The friction force can be quite low if the car is cruising at constant speed.
If skidding, the friction force on all tires combined is M*g*1.2 = 23520 N
To find the frictional force between the tires of a car and the road, you can use the formula:
Frictional force = Coefficient of friction × Normal force
The normal force is the force exerted by the surface perpendicular to the contact surface. In this case, the normal force is equal to the weight of the car, since the car is on a flat surface.
The weight of the car can be calculated using the formula:
Weight = Mass × Acceleration due to gravity
In this case, the mass of the car is given as 2000 kg, and the acceleration due to gravity is approximately 9.8 m/s².
Weight = 2000 kg × 9.8 m/s²
Solving this equation, we find that the weight of the car is 19,600 Newtons (N).
Now we can calculate the frictional force:
Frictional force = 1.2 × 19,600 N
By multiplying the coefficient of friction (1.2) by the weight of the car (19,600 N), we can determine that the frictional force between the tires of the car and the asphalt road is 23,520 Newtons (N).