A student librarian picks up a 2.2 kg book from the floor to a height of 1.05 m. He carries the book 8.3 m to the stacks and places the book on a shelf that is 0.35 m above the floor. How much work does he do on the book?

work=2.2 g*(.35)

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To calculate the work done on the book, we need to use the formula:

Work = Force × Distance × cos(θ)

In this case, the force exerted on the book is equal to the weight of the book, which can be calculated using the formula:

Weight = mass × acceleration due to gravity

Given that the mass of the book is 2.2 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can find the weight of the book:

Weight = 2.2 kg × 9.8 m/s^2

Next, we need to find the vertical distance the book is lifted. The student librarian raises the book from the floor to a height of 1.05 m. Therefore, the lifting distance is 1.05 m.

Once the book is lifted, the student librarian carries it horizontally for a distance of 8.3 m.

The angle (θ) between the force vector and the displacement vector is 0 degrees because the force is acting vertically upwards and the displacement is also vertically upwards.

Using these values, we can calculate the work done on the book:

Work = Weight × Distance × cos(θ)

Work = (Mass × acceleration due to gravity) × Distance × cos(θ)

Work = (2.2 kg × 9.8 m/s^2) × (1.05 m + 0.35 m) × cos(0°)

Work = (2.2 kg × 9.8 m/s^2) × 1.4 m × 1

Now, we can calculate the work:

Work = 2.2 kg × 9.8 m/s^2 × 1.4 m

By simplifying this expression, we can find the final answer.