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April 17, 2014

April 17, 2014

Posted by **Anamika** on Thursday, December 20, 2012 at 12:29pm.

- maths --plse help me.. -
**Steve**, Thursday, December 20, 2012 at 2:48pmHmm. If the cone has radius R and height H, and the cylinder has radius r and height h,

by similar triangles, r/R = (H-h)/H

area of cylinder

a = 2pi r h

= 2pi (R/H) h(H-h)

da/dh = 2pi (R/H) (H-2h)

max a when H = 2h

or, if you don't have calculus to help you, let's pick up here:

a = 2pi (R/H) h(H-h)

= 2pi (R/H) (Hh - h^2)

this is a parabola with vertex (maximum value) when h = H/2

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