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December 18, 2014

December 18, 2014

Posted by **kat** on Thursday, December 20, 2012 at 11:13am.

- Physics -
**Henry**, Friday, December 21, 2012 at 9:20pmd=0.8km @45o+2.625km @90o+0.755km @200o

X=0.8*cos45+2.625*cos90+0.755*cos200.

X = -0.1438 km.

Y=0.8*sin45+2.625*sin90+0.755*sin200.

Y = 2.932 km.

tanAr = Y/X = 2.932/-0.1438 = -20.38943

Ar = -90o

A = -90 + 180 = 90o.

d^2 = X^2 + Y^2 = 8.61730.

d = 2.936 km @ 90o.

The hunter must travel 2.936 km, due

South to return to his car.

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