Physics
posted by kat on .
A hunter game in the woods keeps. Track of his movements from his car he travels 1/2 mile down a trail into the woods that leads directly north east. From there he bushwacks 3500 paces directly north before stopping for a drink. As he is putting his flask away he hears a noise. He heads off after the noise at a heading of 20 degrees south of west after covering a distance of 800 yards he comes to a clearing where he has a clear shot at the buck he has been hearing only 30 yards along the same straight line he has been traveling. He manages to drop the buck on the spot he is standing. From where the buck was dropped. How far and in what direction must the hunter travel to return to the car? Give answer in km and with a percise heading. Assume the hunter has a constant pace lenght of .75 m. Solve algebraicly.

d=0.8km @45o+2.625km @90o+0.755km @200o
X=0.8*cos45+2.625*cos90+0.755*cos200.
X = 0.1438 km.
Y=0.8*sin45+2.625*sin90+0.755*sin200.
Y = 2.932 km.
tanAr = Y/X = 2.932/0.1438 = 20.38943
Ar = 90o
A = 90 + 180 = 90o.
d^2 = X^2 + Y^2 = 8.61730.
d = 2.936 km @ 90o.
The hunter must travel 2.936 km, due
South to return to his car.