Posted by Nicola on Wednesday, December 19, 2012 at 11:54pm.
Na2CO3 + 2AgNO3 = 2NaNO3 + Ag2CO3
each mole of Na2CO3 requires 2 moles of AgNO3, so only half the Na2CO3 is used up.
So, only 0.275 moles of Ag2CO3 are produced, or .275*275.7453 = 75.8g
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