Posted by **LP** on Wednesday, December 19, 2012 at 7:39pm.

Find three consecutive odd integers such that the square of the first increased by product of the other two is 224.

- Math -
**Reiny**, Wednesday, December 19, 2012 at 10:00pm
let the middle number be x

then the 1st is x-2

and the 3rd is x+2

(x-2)^2 + x(x+2) = 224

x^2 - 4x + 4 + x^2 + 2x = 224

2x^2 -2x - 220 = 0

x^2 - x - 110 = 0

(x-11)(x+10) = 0

x = 11 or x = -10, but x is to be odd

so

x = 11

and the three numbers are 9, 11, and 13

check:

9^2 + 11(13) = 224 , YEAH!

## Answer This Question

## Related Questions

- Math - find three consecutive positive odd integers such that the sum of the ...
- math - Determine whether there are 2 consecutive odd integers such that 5 times ...
- math - find three consecutive odd integers such that the sum of the first and ...
- Pre-Algebra - Find two consecutive odd integers such that 5 times the first ...
- quad. eq. - find 3 consecutive integers such that the product of the second and ...
- math - find 3 consecutive odd integers such that the product of the first and ...
- math - the product of two even consecutive integers is 224. find the integers
- math - the product of two even consecutive integers is 224. find the integers
- math - the product of two even consecutive integers is 224. find the integers
- Math - Find two consecutive odd integers such that the square of the larger is ...

More Related Questions