algebra 2
posted by lisa .
2x^25x3 show all the step please thanks

Are you wanting it factorised?
If so:
multiply the constant, in this case '3' by the coefficient of x^2, so:
(2x3=6)
Take the 2 off the coefficient and replace the constant, 3, with 6, so you have:
x^2 5x 6
Find products of 6 that also add to make 5.
The products, in this case, are 6 and 1:
6 multiplied by 1 = 6
6 + 1 = 5
You now have both coefficients of x, so remove the 5 in front of the x in the ORIGINAL equation: '2x^25x3' and replace with '6x + x' so it becomes:
2x^26x+x3
Split the equation between the two coefficients of x:
'2x^26x' and 'x3'
Factorise these separately e.g.
'2x^26x' becomes 2x(x3).
and,
'x3' becomes 1(x3).
As you can see the equation inside both brackets are the same so now take the numbers in front of both brackets:'2x' and '+1' and form a separate bracket: (2x+1)
Discard one of the (x3) brackets and keep the other.
so in brackets: (2x+1) (x3).
x=1/2 or x=3.
Matt 
In short:
2x^25x3 becomes 2x^26x+x3.
Split and factorise for:
2x(x3) 1(x3)
Which becomes:
(2x+1)(x3)
x=1/2 or x=3