March 25, 2017

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2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:
CH4 + NH3 + O2  HCN + H2O
You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions:
• What is the balanced equation for this reaction?
• Which reagent is limiting? Explain why.
• How many grams of hydrogen cyanide will be formed?

  • Chem- REALLY URGENT!!! - ,

    2CH4 + 2NH3 + 3O2  2HCN + 6H2O

    mols CH4 = grams/molar mass CH4 =?
    mols NH3 = grams/molar mass NH3 = ?

    a. Convert mols CH4 to mols HCN using the coefficients in the balanced equation.
    b. Convert mols NH3 the same way.
    c. It is likely that the answers from a and b will not be the same which means one of them is wrong.
    d. The correct answer in limiting reagent problems is ALWAYS the smaller value and the reagent producing that number is the limiting reagent.

    Using the smaller value convert mols to grams. g = mols HCN x molar mass HCN

  • Chem- REALLY URGENT!!! - ,


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