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January 31, 2015

January 31, 2015

Posted by **Emma** on Wednesday, December 19, 2012 at 4:55pm.

solve for x in radians between [0,2pi)

(I mean that it is sine squared x and cosine squared x not sine to the power of 2x or cosine to the power of 2x)

- trig -
**Steve**, Wednesday, December 19, 2012 at 5:00pmfactor out sin*cos to get

2sin*cos(1+2sin*cos) = 0

so,

sin=0: x = 0 or π

or

cos=0: x = π/2 or 3π/2

or

1+sin2x = 0

sin2x = -1

2x = 3π/2: x = 3π/4

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