Posted by **Toung** on Wednesday, December 19, 2012 at 4:47pm.

When a 51.7 gram tennis ball is served, it accelerates from rest to a speed of 41.2 m/s. The impact with the racket gives the ball a constant acceleration over a distance of 49.5 cm. What is the magnitude of the net force acting on the ball in newtons?

- Physics -
**drwls**, Wednesday, December 19, 2012 at 8:08pm
F = m*a

We first need to compute the acceleration, a.

V = sqrt(2aX)

41.2 = sqrt(2*a*0.495)

1697 = 2*a*0.495

a = 1714 m/s^2

F = m*a

= 0.0157 kg*1714 m/s^2

= 88.6 N

Another way to solve this is to equate the final kinetic energy to F*X (work done)

F = (1/2)MV^2/X

= (0.5)(0.0517)*41.2^2/(0.495)

= 88.6 N

- Physics -
**Toung**, Wednesday, December 19, 2012 at 10:19pm
thank you so much

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