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April 19, 2014

April 19, 2014

Posted by **Knights** on Wednesday, December 19, 2012 at 12:29pm.

x^2 =40+12sqrt2

what would be x? BTW if you sqrt both sides it would be double square root so what then? how to simplify?

- double square root problem? -
**Damon**, Wednesday, December 19, 2012 at 2:30pm12 sqrt 2 = x^2 - 40

144 (2) = x^4 -80 x^2 + 1600

x^4 - 80 x^2 + 1312 = 0

graph to find zeros

http://mathportal.org/calculators/polynomials-solvers/polynomial-graphing-calculator.php

zeros at

x = -7.55, -4.80 + 4.80, +7.55

check those in original

+ and - 7.55 works

the 4.8 does not

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