Post a New Question
posted by Anonymous on Wednesday, December 19, 2012 at 12:25pm.
intergrate 3x-4/x^2-4x+4
I assume you mean (3x-4)dx/(x-2)^2 3x dx/(x-2)^2 - 4 dx/(x-2)^2 3[ -2/(x-2) + ln(x-2) ] -4 [ -1/(x-2) ] -6/(x-2) + 3 ln(x-2) + 4/(x-2) -2/(x-2) + 3 ln(x-2)
More Related Questions