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March 26, 2017

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A spring has a force constant of 70000 N/m.
How far must it be stretched for its potential energy to be 21 J?

  • physics - ,

    well, let's see. You are only given two pieces of data, so the manipulation must be simple.

    energy(N-m) = N/m * m^2

    P.E. = 1/2 kx^2
    21 = 1/2 (70000)x^2
    x^2 = .0006
    x = .0245m or 2.45 cm

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