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November 28, 2014

November 28, 2014

Posted by **Anonymous** on Wednesday, December 19, 2012 at 6:50am.

- maths -
**Steve**, Wednesday, December 19, 2012 at 10:57amv = 2/3 pi r^3 + pi r^2 h

d = 4/5 h, so r = 2h/5

but that's the total height. So, in terms of wall height, r = 2h/3

= pi r^2 (2r/3 + h)

1144/21 = pi (2h/3)^2 (2/3 * 2h/3 + h) = 52pi/81 h^3

h = 3 m

so, the wall is 3m high, and the dome is another 2m high, making the whole structure 5m high.

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