Posted by Hep on Wednesday, December 19, 2012 at 3:41am.
V=7.5 m/s
v=1.52 m/s
u=?
u(x)=V(x)+v(x)= 0-vsin42⁰= - 1.52•0.67=-1.02 m/s
u(y)=V(y)+v(y)= V+vcos42⁰=7.5+1.52•0.0.74=8.63 m/s
u=sqrt{u(x)²+ u(y)²}=8.69 m/s
tanβ = u(x)/u(y)=1.02/8.63=0.12
β =6.74⁰ (west of north)
Related Questions
College Physics :/ - a ship is traveling due east at 10 km/h. what must be the ...
Physics - At the entrance channel of a harbor, the tidal current has a velocity ...
Physics - At the entrance channel of a harbor, the tidal current has a velocity ...
Trig. - Help with this problem please. I don't get it at all. A ship is ...
Physics - A sip is heading due west at a steady speed of 15km/hr. A current of ...
Physics - At the entrance channel of a harbor, the tidal current has a velocity ...
Mechanics AQA igher - A ship is being steered due east. A current is flowing ...
Physics - A passenger walks from one side of a ferry to the other as it ...
Physics - A passenger walks from one side of a ferry to the other as it ...
science - a boat heading due north crosses a wide river with speed of 12km/h ...
For Further Reading