Posted by ellis on Tuesday, December 18, 2012 at 9:49pm.
3x-9=12
3x = 12+9
3x = 21
x = 7 , which is a member of your solution set
y^2 - 5y - 11 = 13
y^2 - 5y - 24 - 0
(y-8)(x+3) = 0
y = 8 or y = -3
only y=8 is a solution, since -3 is not part of your solution set.
so i dont have to plug in each number?
yes, you could do that.
I don't know what grade level you are at.
The second question involved solving a quadratic.
If you don't know what that is, then plugging in each value of the replacement set would be your way of doing it.
so i dont have to plug in each number?
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