Posted by **ellis** on Tuesday, December 18, 2012 at 9:49pm.

find the solution of each equation if the replacement sets are x:{1,3,5,7,9} and y:{2,4,6,8,10}.

3x-9=12

y^2-5y-11=13

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**Reiny**, Tuesday, December 18, 2012 at 9:55pm
3x-9=12

3x = 12+9

3x = 21

x = 7 , which is a member of your solution set

y^2 - 5y - 11 = 13

y^2 - 5y - 24 - 0

(y-8)(x+3) = 0

y = 8 or y = -3

only y=8 is a solution, since -3 is not part of your solution set.

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**ellis**, Tuesday, December 18, 2012 at 9:57pm
so i dont have to plug in each number?

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**Reiny**, Tuesday, December 18, 2012 at 10:16pm
yes, you could do that.

I don't know what grade level you are at.

The second question involved solving a quadratic.

If you don't know what that is, then plugging in each value of the replacement set would be your way of doing it.

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