Post a New Question

chemistry

posted by on .

8.58g of coastic soada was dissolved to produce a solution of 500cm3 .to neutralize 50cm3 of this solution 15cm3 of 0.4M HCl was consumed .(coastic soada = Na2CO3.XH2O ) find the value of X?

  • chemistry - ,

    Note the correct spelling of caustic soda. Also, correct sentence structure helps us read these problems better.
    How many mols HCl did you use? That's M x L = 0.4M x 0.015L = 0.006.
    How many grams were in the solution you titrated. That's 8.58 x 50/500 = 0.858 g.
    Then mols = grams/molar mass and rearrange to molar mass = grams/mols.
    0.858/0.006 = about 143.
    Subtract Na2CO3 = -106
    Remainder is 37 and 37/18 = 2.05 mols and I would round that to 2.0 for X.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question