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March 27, 2015

March 27, 2015

Posted by **Jimmy-can someone please help** on Tuesday, December 18, 2012 at 4:50pm.

The vertex is (3,11) and the y-intercept is -2

So, f(x)=

**Please help me understand how to do this question. Could you please show work?**

- calculus -
**Steve**, Tuesday, December 18, 2012 at 6:20pmcome on, guy. You should be getting the hang of these by now.

the vertex says

f(x) = a(x-3)^2 + 11

the point (0,-2) says

-2 = 9a+11

a = -13/9

f(x) = -13/9 (x-3)^2 + 11

would have been nicer with a y-intercept of +2.

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