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September 30, 2014

September 30, 2014

Posted by **amaka** on Tuesday, December 18, 2012 at 4:17pm.

- math -
**Jennifer**, Wednesday, December 19, 2012 at 8:17pmFor the square with area 25 yd^2,

x^2 = 25; x = 5; where x is the length of a side of the square. The perimeter of this square is 5*4 = 20

For the square with area 5 yd^2,

y^2 = 5; y = 5^0.5; where y is the length of the side of this square. The perimeter of this square is 4*(5^0.5)

The total yards of fencing needed to enclose both is the sum of the perimeters of both squares, or 20 + 4*(5^0.5)

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