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March 1, 2015

Posted by **Neil** on Tuesday, December 18, 2012 at 3:46pm.

- Math For College Readiness -
**Neil**, Tuesday, December 18, 2012 at 8:57pmThe only work so far I know to do is,

=(3w - 1) / (w^2 + w - 6) - (2 - w) /(w - 1) - (w) / (w - 1)

= (3w - 1) / (w - 1) (2w + 3) -(w + 2) / (w - 1) - (w) / (w - 1)

I don't know what to do from here.

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