Math
posted by M. Pannell on .
For the function, find the average rate of change of f from 1 to x:f(x)f(1)/x1
x does not equal 1
f(x) = x3 + x

avg rate is slope of secant:
[f(x)f(1)]/[x1]
= [(x^3+x)(1^3+1)]/[x1]
= (x^3+x2)/(x1)
= x^2+x+2