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July 22, 2014

July 22, 2014

Posted by **akela** on Tuesday, December 18, 2012 at 12:27am.

- calculus -
**drwls**, Tuesday, December 18, 2012 at 12:44amWhat is the "given line" that the solid volume revolves around?

- calculus -
**drwls**, Tuesday, December 18, 2012 at 12:46amShould the word "above" in the last line be "about"? Then the question would make sense.

- calculas -
**Steve**, Tuesday, December 18, 2012 at 10:02amusing washers, the volume is

∫[0,π/10] π R^2-r^2 dx

where R=2 and r = √(sin5x) + 1

v = ∫[0,π/10] π (4 - (√(sin5x)+1)^2) dx

I think you are in trouble.

∫√(sin5x) dx

cannot be evaluated using elementary functions.

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