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October 20, 2014

October 20, 2014

Posted by **Shadow** on Monday, December 17, 2012 at 9:32pm.

S(subscript 8) + O( subscript 2) -> SO3

Could you explain why it O3 when S valence is -2? Thanks

- Chem:DrBob -
**DrBob222**, Monday, December 17, 2012 at 10:53pmYes. S is +6 in SO3. Each O is -2; 3*-2 = -6 so for SO3 to be neutral (as all compounds are) S must be +6. That's part of the problem, I suppose, and S DOES have -2 in H2S and the sulfides (such as Na2S, K2S, BaS, etc) but S may have valences of -2, 0, +4 and +6 and those are quite common. SO2 is an example of +4. Hope this helps.

- Chem:DrBob -
**Shadow**, Monday, December 17, 2012 at 11:44pmSo since it S3O6, it was reduce to SO3?

- Chem:DrBob -
**DrBob222**, Tuesday, December 18, 2012 at 12:01amYes, SO3 is the empirical formula.

- Chem:DrBob -
**DrBob222**, Tuesday, December 18, 2012 at 12:02amYes, SO3 is the empirical formula. It may be the molecular formula, also.

- Chem:DrBob -
**Shadow**, Tuesday, December 18, 2012 at 12:08amWhen you write the formula in word equation would it be : Octasilicon and oxygen reacted to produce sulfur trioxide?

Would this be the balance equation?

S8 + 12O2 -> 8SO3

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