Posted by Shadow on Monday, December 17, 2012 at 9:32pm.
Thank you for the informative answer yesterday. I hope you can help me with this one too. Thanks
S(subscript 8) + O( subscript 2) > SO3
Could you explain why it O3 when S valence is 2? Thanks

Chem:DrBob  DrBob222, Monday, December 17, 2012 at 10:53pm
Yes. S is +6 in SO3. Each O is 2; 3*2 = 6 so for SO3 to be neutral (as all compounds are) S must be +6. That's part of the problem, I suppose, and S DOES have 2 in H2S and the sulfides (such as Na2S, K2S, BaS, etc) but S may have valences of 2, 0, +4 and +6 and those are quite common. SO2 is an example of +4. Hope this helps.

Chem:DrBob  Shadow, Monday, December 17, 2012 at 11:44pm
So since it S3O6, it was reduce to SO3?

Chem:DrBob  DrBob222, Tuesday, December 18, 2012 at 12:01am
Yes, SO3 is the empirical formula.

Chem:DrBob  DrBob222, Tuesday, December 18, 2012 at 12:02am
Yes, SO3 is the empirical formula. It may be the molecular formula, also.

Chem:DrBob  Shadow, Tuesday, December 18, 2012 at 12:08am
When you write the formula in word equation would it be : Octasilicon and oxygen reacted to produce sulfur trioxide?
Would this be the balance equation?
S8 + 12O2 > 8SO3
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