a crate mass 20 kg is being pushed by a person with horizontal force of 63 N, moving with a constant velocity [E]. find the force of kinetic friction.
Well, well, seems like this crate is playing hard to get with the person pushing it! Let me see if I can help you out here.
If the crate is moving with a constant velocity, that means the net force acting on it is zero. So, we need to find the force of kinetic friction that is opposing the force applied by the person.
Now, the force of kinetic friction can be calculated using the equation:
Force of kinetic friction = μ * normal force,
where μ is the coefficient of kinetic friction and the normal force is the force exerted by the crate on the surface it is on.
Since the crate is not accelerating vertically, the normal force is equal to the weight of the crate, which is given by:
Normal force = mass * gravity,
where gravity is approximately 9.8 m/s².
So, let's plug in the numbers into this clownish equation!
Normal force = 20 kg * 9.8 m/s² = 196 N.
Now, comes the coefficient of kinetic friction. Since it's not given, I'm going to assume it's my coefficient of humor, which is pretty high (just kidding!).
Let's assume the coefficient of kinetic friction is 0.4 (which is a common value for wood on wood).
Force of kinetic friction = 0.4 * 196 N = 78.4 N.
So, the force of kinetic friction is approximately 78.4 Newtons. I hope this clownish explanation didn't slide away from you!
To find the force of kinetic friction acting on the crate, we need to use Newton's second law and understand that the crate is moving with a constant velocity.
1. Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration. Since the crate is moving with a constant velocity, the acceleration is zero. Therefore, the net force acting on the crate is also zero.
2. The net force acting on the crate can be determined by subtracting the force of kinetic friction from the applied force. In this case, the applied force is 63 N.
3. Since the crate is moving with a constant velocity, the force of kinetic friction is equal in magnitude and opposite in direction to the applied force. Therefore, the force of kinetic friction is 63 N in the opposite direction [W].
So, the force of kinetic friction acting on the crate is 63 N [W].
To find the force of kinetic friction, we first need to understand that the crate is moving with a constant velocity. This means that the net force acting on the crate is zero since it is not accelerating.
The force pushing the crate horizontally is given as 63 N towards the east [E]. In this case, the force of kinetic friction acts in the opposite direction (west). Let's assume it is Fk.
Since the crate is not accelerating, we can apply Newton's second law which states that the sum of all forces acting on an object is equal to the product of mass and acceleration. In this case, the acceleration is zero.
Hence, the equation becomes:
Sum of forces = mass × acceleration
Fk - 63 N = 20 kg × 0 m/s²
Fk = 63 N
Therefore, the force of kinetic friction in this scenario is 63 N in the opposite direction of the applied force, which is west.
Force friction is 63 N. Since the velocity is constant, there is no acceleration, and no force trying to prevent the crate from moving.
F is given as F = ma.
F is the net force: Fa (force applied) - Ff (force friction). If there is no acceleration, 'a' becomes zero, causing mass to cancel out as well, leaving you with F = 0, which means there is no change in the forces acting on the crate.