Posted by naomi on Monday, December 17, 2012 at 5:51pm.
who is correct and why?
chloe jonas
3<2x5<7 3<2x5<7
3<2x<12 8<2x<7
3/2<x<6 4<x<7/2
2) solve each inequality for x. assume a is constant and a>0
a. 3<ax+1< or equal to 5
b. 1/ax+6<1 or 2ax>8
3) create an example of a compound inequality containing or that has infinitely many solutions.

algebra 1  naomi, Monday, December 17, 2012 at 5:53pm
chole 3<2x5<7
3<2x<12
3/2<x<6
jonas
3<2x5<7
8<2x<7
4<x<7/2

algebra 1  Henry, Tuesday, December 18, 2012 at 10:21pm
3<2x5<7.
3+5<2x<7+5
8<2x<12
4<X<6.
Note: Add 5 to BOTH sides of the compound inequality.
2a. 3<ax+1<=5.
31<ax<=51
4<ax<=4
4/a<X<=4/a.
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