Posted by **naomi** on Monday, December 17, 2012 at 5:51pm.

who is correct and why?

chloe jonas

3<2x-5<7 3<2x-5<7

3<2x<12 8<2x<7

3/2<x<6 4<x<7/2

2) solve each inequality for x. assume a is constant and a>0

a. -3<ax+1< or equal to 5

b. -1/ax+6<1 or 2-ax>8

3) create an example of a compound inequality containing or that has infinitely many solutions.

- algebra 1 -
**naomi**, Monday, December 17, 2012 at 5:53pm
chole 3<2x-5<7

3<2x<12

3/2<x<6

jonas

3<2x-5<7

8<2x<7

4<x<7/2

- algebra 1 -
**Henry**, Tuesday, December 18, 2012 at 10:21pm
3<2x-5<7.

3+5<2x<7+5

8<2x<12

4<X<6.

Note: Add 5 to BOTH sides of the compound inequality.

2a. -3<ax+1<=5.

-3-1<ax<=5-1

-4<ax<=4

-4/a<X<=4/a.

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