An automobile of mass 1.46 E3 kg rounds a curve of radius 25.0 m with a velocity of 15.0 m/s. The centripetal force exerted on the automobile while rounding the curve is?

1.31 E 4N

The centripetal force exerted on an object moving in a circular path is given by the formula:

F = (m * v^2) / r

where:
F is the centripetal force
m is the mass of the object
v is the velocity of the object
r is the radius of the circular path

Given:
m = 1.46E3 kg
v = 15.0 m/s
r = 25.0 m

Plugging these values into the formula, we get:

F = (1.46E3 kg * (15.0 m/s)^2) / (25.0 m)

Calculating this, we get:

F = (1.46E3 kg * 225.0 m^2/s^2) / 25.0 m

F = 13.14E3 N

Therefore, the centripetal force exerted on the automobile while rounding the curve is approximately 13.14E3 N.

To find the centripetal force exerted on the automobile while rounding the curve, we can use the formula:

F = (m * v^2) / r

Where:
F = centripetal force
m = mass of the automobile
v = velocity of the automobile
r = radius of the curve

Given:
m = 1.46E3 kg (mass of the automobile)
v = 15.0 m/s (velocity of the automobile)
r = 25.0 m (radius of the curve)

Substituting these values into the formula, we have:

F = (1.46E3 kg * (15.0 m/s)^2) / 25.0 m

First, let's calculate the numerator: (1.46E3 kg * (15.0 m/s)^2)

1.46E3 kg * (15.0 m/s)^2 = 1.46E3 kg * (225 m^2/s^2)

Multiply 225 by 1.46E3:
225 * 1.46E3 = 3.285E5

Now, we have:
F = (3.285E5) / 25.0 m

Divide 3.285E5 by 25.0:
3.285E5 / 25.0 m = 1.314E4 N

Therefore, the centripetal force exerted on the automobile while rounding the curve is approximately 1.314E4 N.

F= mv²/R