Post a New Question

Calculus

posted by on .

Find the area between the following curves y1= x2−4x+3 y2=−x2+2x+3

  • Calculus - ,

    The curves intersect at (0,4) and (3,0)

    area = ∫[0,3] (-x^2+2x+3) - (x^2-4x+3) dx
    = ∫[0-3] 6x - 2x^2 dx
    = 3x^2 - 2/3 x^3 [0,3]
    = 9

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question