posted by anita on .
The fictitious compound, pandemonium carbonate Pn(CO3)2 hase a Ksp=3.091×10−9 M3 in water at room temperature. Calculate the solubility of Pn(CO3)2 in an aqueous solution of 1.11 M pandemonium sulfate Pn(SO4)2 (aq). Express your answer in units of molarity.
2.639 x 10^-5