Posted by **Mackenzie** on Monday, December 17, 2012 at 12:08am.

Evaluate the integral by changing to spherical coordinates.

The outer boundaries are from 0 to 1.

The middle one goes from -sqrt(1-x^2) to sqrt(1-x^2)

The inner one goes from -sqrt(1-x^2-z^) to sqrt(1-x^2-z^)

for 1/sqrt(x^2+y^2+z^2) dydzdx

I don't understand how to get the limits of integration. I know for rho it will be from 0 to 1. I want to know the process to get the boundaries for phi and theta since I have a few other similar problems to do.

- Calculus -
**Steve**, Monday, December 17, 2012 at 12:31am
you are integrating over the whole sphere, so

0 <= p <= 1 (inside-outside)

0 <= φ <= 2π (whole x-y plane)

0 <= θ <= π (top-to-bottom of sphere)

There must be some examples in your text. And there are surely some online.

- Calculus -
**Mackenzie**, Monday, December 17, 2012 at 1:10am
The solution says the the boundary for phi is from 0 to pi as well as the one for theta.

- Calculus -
**Steve**, Monday, December 17, 2012 at 4:17am
I'd have to think about it, but you obviously have both halves of the circle and both halves of the sphere.

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