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a bolwing ball of mass 2.00 kg strikes a stationary pin of mass 5.00 x 10^2 g. the collision lasts for .60s after which the pin moves off with a velocity of 12.0 m/s [w]
a)accel of pin during the collision
b)force exerted by bowling ball on the pin
c)the accel of the bowling ball during collision

  • physics -

    a) acceleration = (Pin velocity change)/(0.60 s)
    = 20 m/s^2 = a

    b) F = M(pin)*a = 0.500 kg*20 m/s^2
    = 10 Newtons
    The forces F on ball and pin are equal and opposite, so
    c) a(ball) = F/M(ball) = 10/2 = 5 m/s^2

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