Monday

July 28, 2014

July 28, 2014

Posted by **Mackenzie** on Sunday, December 16, 2012 at 9:22pm.

The outer boundaries are from 0 to 1.

The middle one goes from -sqrt(1-x^2) to sqrt(1-x^2)

The inner one goes from -sqrt(1-x^2-z^) to sqrt(1-x^2-z^)

for 1/sqrt(x^2+y^2+z^2) dydzdx

I don't understand how to get the limits of integration. I know for rho it will be from 0 to 1. I want to know the process to get the boundaries for phi and theta since I have a few other similar problems to do.

**Related Questions**

Calculus - Evaluate the integral by changing to spherical coordinates. The outer...

Calculus - Evaluate the integral by changing to spherical coordinates. The outer...

Calculus - Evaluate the integral by changing to spherical coordinates. The outer...

Calculus - Evaluate the indefinite integral: 8x-x^2. I got this but I the ...

Calculus - Find the volume of the solid whose base is the region in the xy-plane...

Calculus URGENT test tonight - Integral of: __1__ (sqrt(x)+1)^2 dx The answer is...

math - use spherical coordinates to evaluate the triple integral of (e^-(x^2+y^2...

calc check: curve length - Find the length of the curve y=(1/(x^2)) from ( 1, 1...

Calculus - Evaluate, in spherical coordinates, the triple integral of f(rho,...

Calculus II - Evaluate using u-substitution: Integral of: 4x(tan(x^2))dx ...