Intermediate Algebra
posted by Anonymous on .
For the quadratic equation y=(x3)^22. Determine: A) whether the graph opens up or down; B) the yintercept; C)the xintercepts; D) the points of the vertex. and D) graph the equation with at lease 10 pairs of points.

y=(x3)^22
or
y=+1(x3)^22 vs y = a(xp)^2 + q
since a=1 , a> 0 , so it opens upwards
y=intercept, let x = 0
y = (3)^2  2 = 7
xintercept, let y = 0
(x3)^2  2 = 0
(x3)^2 = 2
x3 = ± √2
x = 3 ± √2
"points of the vertex " ????
the vertex IS a point, it does not have points, it has coordinates
they are (3,2) , (from (p,q) )
For D) just pick any suitable values for x, evaluate the corresponding y's and plot.
(pick values of x immediately above and below +3 )