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March 29, 2017

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A 1.13 × 103 kg car accelerates uniformly from rest to 10.6 m/s in 3.22 s.
What is the work done on the car in this time interval?
Answer in units of J

  • physics - ,

    W = F*d.

    a = (V-Vo)/t
    a = (10.6-0)/3.22 = 3.29 m/s^2.

    F = m&a = 1130 * 3.29 = 3720 N.

    d = 0.5a*t^2 = 0.5*3.29*(3.22^2)=17.1 m.
    W = 3720 * 17.1 = 63,448 Joules.

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