Tuesday

March 31, 2015

March 31, 2015

Posted by **Mackenzie** on Sunday, December 16, 2012 at 6:20pm.

The outer boundaries are from 0 to 1.

The middle one goes from -sqrt(1-x^2) to sqrt(1-x^2)

The inner one goes from -sqrt(1-x^2-z^) to sqrt(1-x^2-z^)

for 1/sqrt(x^2+y^2+z^2) dydzdx

I don't understand how to get the limits of integration. I know for rho it will be from 0 to 1. I want to know the process to get the boundaries for phi and theta since I have a few other similar problems to do.

- Calculus -
**Steve**, Monday, December 17, 2012 at 12:24amyou are integrating over the whole sphere, so

0 <= p <= 1 (inside-outside)

0 <= φ <= 2π (whole x-y plane)

0 <= θ <= π (top-to-bottom of sphere)

There must be some examples in your text. And there are surely some online.

**Answer this Question**

**Related Questions**

Calculus - Evaluate the integral by changing to spherical coordinates. The outer...

Calculus - Evaluate the integral by changing to spherical coordinates. The outer...

Calculus - Evaluate the integral by changing to spherical coordinates. The outer...

Calculus - Evaluate the indefinite integral: 8x-x^2. I got this but I the ...

Math Help please!! - Could someone show me how to solve these problems step by ...

Mathematics - sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So...

Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...

Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...

math calculus please help! - l = lim as x approaches 0 of x/(the square root of...

Math - How do you find a square root of a number that's not a perfect square? I'...