What is the acceleration of a 66 kg block of cement when pulled sideways with a net force of 597 N? Answer in units of m/s 2.
a=F/m
To determine the acceleration of the block of cement, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
The equation for Newton's second law is:
F = ma
Where:
F is the net force acting on the object
m is the mass of the object
a is the acceleration of the object
In this case, the net force applied is 597 N, and the mass of the block of cement is 66 kg. Therefore, the equation becomes:
597 N = 66 kg * a
To find the acceleration (a), we can isolate it on one side of the equation by dividing both sides by the mass of the object:
597 N / 66 kg = a
Now, we can calculate the acceleration:
a ≈ 9.05 m/s^2
Therefore, the acceleration of the 66 kg block of cement, when pulled sideways with a net force of 597 N, is approximately 9.05 m/s^2.