The lethal inhalation dose of Sarin for a 200lb person has been determined to be 0.0015 mg. Determine the LD50 of Sarin that researchers used to calculate this lethal inhalation dose.
1.4 x 10-4 mg/kg
0.16 x 10-4 mg/kg
1.8 x 10-5 mg/kg
0.00023 mg/kg
I believe this can be done with the right factor. Convert 200 lb to kg; I think that is about 91 kg but you need to do it more accurately. Then
(?mg/kg) x 91 = 0.0015 mg.
Solve for ?mg. I have about 1.6E-5 mg/kg and that is one of the answers.
0.16 x 10-4 mg/kg
To determine the LD50 (Lethal Dose 50%) of Sarin that researchers used to calculate the lethal inhalation dose for a 200lb person, we need to convert the weight of the person from pounds to kilograms.
To convert pounds to kilograms, we divide the weight in pounds by 2.2046 (since 1 pound is approximately equal to 0.4536 kilograms).
So, for a 200lb person, the weight in kilograms is calculated as follows:
200 lb ÷ 2.2046 = 90.72 kg (rounded to two decimal places)
Now that we have the weight in kilograms, we can determine the LD50 (Lethal Dose 50%) in mg/kg.
Given the possible options:
1.4 x 10-4 mg/kg
0.16 x 10-4 mg/kg
1.8 x 10-5 mg/kg
0.00023 mg/kg
We need to match the LD50 with the calculated weight.
From the given options, the closest match to our calculated weight of 90.72 kg is:
0.16 x 10-4 mg/kg
Therefore, the LD50 of Sarin that researchers used to calculate the lethal inhalation dose for a 200lb person is 0.16 x 10-4 mg/kg.