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Posted by on Saturday, December 15, 2012 at 4:58pm.

Five forces act on an object.

(1) 63 N at 90°
(2) 40 N at 0°
(3) 83 N at 270°
(4) 40 N at 180°
(5) 50 N at 60°

What are the magnitude and direction of a sixth force that would produce equilibrium?

  • Physics - , Saturday, December 15, 2012 at 5:21pm

    find sum in x direction
    63 cos 90 + 40 cos 0 + 83 cos 270 + 40 cos 180 + 50 cos 60
    =50 cos 60 = 25 N at 0 deg
    find sum in y direction
    63 sin 90 + 40 sin 0 etc = 23.3
    tan theta = 23.3/25 = .932
    theta = 43
    we want equal and opposite
    so 43 + 180 = 223 degrees
    magnitude = sqrt (625+543)
    = 34.2 Newtons

  • Physics - , Thursday, February 5, 2015 at 10:52am

    For others to be able to solve:
    I'm using variables since I'm use to computer science
    N = newtons // number after is force number, x is angle

    T1 = N1 cos A, N2 cos A, N3 cos A, etc
    T2 = N1 sin A, N2 sin A, N3 sin A, etc
    D = TAN-1(T1/T2) //use calculator
    direction = D + 180
    magnitude = sqrt(T1ˆ2 + T2ˆ2)

    I liked your answer Damon.

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