Posted by Praphul on Saturday, December 15, 2012 at 4:48pm.
y = k x^2 + b x + c
x , y
(0 ,3 )
(2 , 10 )
(14, 50 )
3 = k (0)^2 + b (0) + c
10 = k(2)^2 + b (2) + c
50 = k (14)^2 + b (14) + c
so
c = 3
7 = 4 k + 2 b
47 = 196 k + 14 b
49 = 28 k + 14 b
47 = 196 k + 14 b
-------------------subtract
2 = - 168 k
k = - .0119
then
7 = 4(-.0119) + 2 b
b = 3.523
so
y = -.0119 x^2 + 3.523
You can take it from there. Find the vertex by completing the square uness you know calculus, then find y at x = 295
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