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February 28, 2015

February 28, 2015

Posted by **Praphul** on Saturday, December 15, 2012 at 4:48pm.

- Math -
**Damon**, Saturday, December 15, 2012 at 5:12pmy = k x^2 + b x + c

x , y

(0 ,3 )

(2 , 10 )

(14, 50 )

3 = k (0)^2 + b (0) + c

10 = k(2)^2 + b (2) + c

50 = k (14)^2 + b (14) + c

so

c = 3

7 = 4 k + 2 b

47 = 196 k + 14 b

49 = 28 k + 14 b

47 = 196 k + 14 b

-------------------subtract

2 = - 168 k

k = - .0119

then

7 = 4(-.0119) + 2 b

b = 3.523

so

y = -.0119 x^2 + 3.523

You can take it from there. Find the vertex by completing the square uness you know calculus, then find y at x = 295

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