Posted by **JoeBob** on Saturday, December 15, 2012 at 3:11pm.

A latex balloon, wall thickness 3.091 x 10-4 m, contains helium at a concentration of 0.35 kg m-3. Under these conditions the total surface area of the balloon is 0.88 m2. The diffusion coefficient of He in latex at room temperature is 4.9 x 10-9 m2s-1. Calculate the rate of helium effusion (in g/hr) from the balloon.

- Physics -
**Elena**, Saturday, December 15, 2012 at 3:43pm
Ficks Law

M= -D(Δρ/Δx)A,

where

M = m/t = mass flux [kg/s],

D= 4.910 ⁻⁹ m ²/s is the diffusion coefficient (diffusivity) [m²/s],

Δρ/Δx is the gradient of density [kg/m⁴],

A is the area [m²].

M= - 4.910⁻⁹(0 - 0.35)/3.09110⁻⁴)0.88 =

4.910⁻⁹0.350.88/3.09110⁻⁴=

=4.8810⁻⁶ kg/s= 17.58 g/hr

- Physics -
**Eric**, Saturday, December 15, 2012 at 9:06pm
Thank you Elena

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