Ms. Tenley's class has 25 students. Two of the students have visited no other countries other than the United States. Five of the students have visited at least 1 other country. Ten students have visited 2, four students have visited 3, 3 students have visited 4, and 1 student have visited 5.
12 students are girls, 13 students are boys. Ten boys and 8 girls have visited two or more countries.
If a student from Ms. Tenley's class is chosen at random, what is the probability that the student selected is a boy who had visited fewer than 2 countries outside the United States or a girl who has visited two or more countries outside the United States? Express your answer in a common fraction.
To find the probability of selecting a boy who has visited fewer than 2 countries outside the United States or a girl who has visited two or more countries outside the United States, we need to calculate the number of favorable outcomes and divide it by the total number of possible outcomes.
The number of boys who have visited fewer than 2 countries outside the United States is 13 - 10 = 3.
The number of girls who have visited two or more countries outside the United States is 8.
So, the total number of favorable outcomes is 3 + 8 = 11.
The total number of students in Ms. Tenley's class is 25.
Therefore, the probability of selecting a student who is a boy and has visited fewer than 2 countries outside the United States or a girl who has visited two or more countries outside the United States is 11/25.