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March 5, 2015

March 5, 2015

Posted by **yaya** on Saturday, December 15, 2012 at 12:36pm.

f(x)2/3x^3+5/2x^2-3x.

a) Find

i. The inflection point.

ii. The y-intercept and x-intercept.

b) Sketch the graph of f(x).

i have already try it..but i dont understand.. which graph that is true.. the first or second ? and how to calculate the x,y intercept,and inflection point? i hope you can help me to solve this ..

- calculus ..>steve -
**Steve**, Saturday, December 15, 2012 at 12:49pmy = 2/3 x^3 + 5/2 x^2 - 3x

y' = 2x^2 + 5x - 3

y'' = 4x + 5

inflection where y''=0 -- at x=-5/4

intercepts at (0,0)

and at x = 3/8 (-5±√57)

Looks like you need to review the meanings of 1st and second derivatives.

- calculus ..>steve -
**Elsi**, Saturday, December 15, 2012 at 1:35pmremember that the first derivative gives you the max's and min's and the second derivative tells you concavity and inflection points

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