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April 18, 2014

April 18, 2014

Posted by **Anonymous** on Saturday, December 15, 2012 at 8:58am.

- maths --plse help me.. -
**Steve**, Saturday, December 15, 2012 at 11:03amIf the radius of the cylinder is r,

v = πr^2 h, so h = v/(πr^2)

a = 2πrh

now the sheet is w by h, so w = 2πr by v/(πr^2)

the volume of the box is thus

1/2 (w-1)(h-1) = 1/2 (2πr-1)(v/(πr^2) - 1)

since no information was given regarding the relative dimensions of the cylinder, the rectangular sheet could be anything between long and skinny or square.

- maths --plse help me.. -
**Jay Bankoti**, Sunday, November 24, 2013 at 10:57amSteve, dont lose patience.This problem does have answer, only thing is one should think out of the box. Let me tell you how it goes:

Volume of cylinder= (pi) (r)(r)(h)= 48.125

(r)(r)h = 15.3125

15.3125 is not a perfect square. To make it perfect square, h should be 5cm.

Now (r)(r)=15.3125/5 = 3.0625 which makes r = 1.75cm

Therefore, rectangular sheet has length of 2(pi)(r)=11cm and width (h) of 5cm.

After cutting a square of 0.5cm from each corner, the dimension of the cuboid becomes:

Length=11-1=10cm; Breadth=5-1=4cm; Height=0.5cm.

Therefore, Volume of cuboid= 10 x 4 x 0.5 = 20 cubic cm.

Thank you for reading it!

Have a nice day bro!

Jay Bankoti

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