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Homework Help: chemistry

Posted by anita on Saturday, December 15, 2012 at 4:54am.

A latex balloon, wall thickness 3.091 x 10-4 m, contains helium at a concentration of 0.35 kg m-3. Under these conditions the total surface area of the balloon is 0.57 m2. The diffusion coefficient of He in latex at room temperature is 4.9 x 10-9 m2s-1. Calculate the rate of helium effusion (in g/hr) from the balloon.

• chemistry - Shakti, Saturday, December 15, 2012 at 6:02am

  maybe:
  0.52*(4.9*10^-9)*(concentration in mole/0.52)
  then multiply solution (molar flow rate) with molar mass of helium.
  solution should be effusion rate.
  its just a suggestion, all other interested are invited to post their opinion/formula...
  

• chemistry - Ling, Saturday, December 15, 2012 at 6:22am

  Could someone insert the data into the formula?
  

• chemistry - Antonio, Saturday, December 15, 2012 at 6:22am

  This is a question from the second midterm of 3.091x by edx. Stop cheating, it's silly and pointless.
  

• chemistry - chelo, Saturday, December 15, 2012 at 8:10pm

  what is the formula?
  

• chemistry - Stud, Saturday, December 15, 2012 at 11:21pm

  Fick’s Law
  M= -D•(Δρ/Δx)•A,
  where
  M = m/t = mass flux [kg/s],
  D= 4.9•10 ⁻⁹ m ²/s is the diffusion coefficient (diffusivity) [m²/s],
  Δρ/Δx is the gradient of density [kg/m⁴],
  A is the area [m²].
  
  M= - 4.9•10⁻⁹•(0 - 0.35)/3.091•10⁻⁴)•0.88 =
  4.9•10⁻⁹•0.35•0.88/3.091•10⁻⁴=
  =4.88•10⁻⁶ kg/s= 17.58 g/hr
  

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