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Homework Help: Chemistry (balloon)

Posted by T on Saturday, December 15, 2012 at 2:49am.

A latex balloon, wall thickness 3.091 x 10-4 m, contains helium at a concentration of 0.3 kg m-3. Under these conditions the total surface area of the balloon is 0.33 m2. The diffusion coefficient of He in latex at room temperature is 4.9 x 10-9 m2s-1. Calculate the rate of helium effusion (in g/hr) from the balloon.

• Chemistry (balloon) - ., Saturday, December 15, 2012 at 3:41am

  A latex balloon, wall thickness 3.091 x 10-4 m, contains helium at a concentration of 0.7 kg m-3. Under these conditions the total surface area of the balloon is 0.52 m2. The diffusion coefficient of He in latex at room temperature is 4.9 x 10-9 m2s-1. Calculate the rate of helium effusion (in g/hr) from the balloon.
  

• Chemistry (balloon) - Antonio, Saturday, December 15, 2012 at 6:23am

  This is a question from the second midterm of 3.091x by edx. Stop cheating, it's silly and pointless.
  

• Chemistry (balloon) - Anonymous, Saturday, December 15, 2012 at 2:31pm

  42.8
  

• Chemistry (balloon) - qpt, Saturday, December 15, 2012 at 4:50pm

  How did you get it? could you show the data in the formula? Thank you
  

• Chemistry (balloon) - chelo, Saturday, December 15, 2012 at 5:51pm

  THE FORMULA
  

• Chemistry (balloon) - anono, Saturday, December 15, 2012 at 10:41pm

  A latex balloon, wall thickness 3.091 x 10-4 m, contains helium at a concentration of 0.94 kg m-3. Under these conditions the total surface area of the balloon is 0.53 m2. The diffusion coefficient of He in latex at room temperature is 4.9 x 10-9 m2s-1. Calculate the rate of helium effusion (in g/hr) from the balloon.
  

• Chemistry (balloon) - Stud, Saturday, December 15, 2012 at 11:19pm

  Fick’s Law
  M= -D•(Δρ/Δx)•A,
  where
  M = m/t = mass flux [kg/s],
  D= 4.9•10 ⁻⁹ m ²/s is the diffusion coefficient (diffusivity) [m²/s],
  Δρ/Δx is the gradient of density [kg/m⁴],
  A is the area [m²].
  
  M= - 4.9•10⁻⁹•(0 - 0.35)/3.091•10⁻⁴)•0.88 =
  4.9•10⁻⁹•0.35•0.88/3.091•10⁻⁴=
  =4.88•10⁻⁶ kg/s= 17.58 g/hr
  

• Chemistry (balloon) - nenita, Sunday, December 16, 2012 at 1:06pm

  thanks stud
  

• Chemistry (balloon) - me, Sunday, December 16, 2012 at 5:50pm

  HOW CAN I SOLVE WITH THESE NUMBERS?
  A latex balloon, wall thickness 3.091 x 10-4 m, contains helium at a concentration of 0.82 kg m-3. Under these conditions the total surface area of the balloon is 0.5 m2. The diffusion coefficient of He in latex at room temperature is 4.9 x 10-9 m2s-1. Calculate the rate of helium effusion (in g/hr) from the balloon.
  

• Chemistry (balloon) - Anonymous, Sunday, December 16, 2012 at 11:05pm

  how do you approach and solve it?
  

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